11c^2+27c+14=2c^2

Solution for 11c^2+27c+14=2c^2 equation:

11c^2+27c+14=2c^2

We move all terms to the left:

11c^2+27c+14-(2c^2)=0

determiningTheFunctionDomain
11c^2-2c^2+27c+14=0

We add all the numbers together, and all the variables

9c^2+27c+14=0

a = 9; b = 27; c = +14;
Δ = b2-4ac
Δ = 272-4·9·14
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-15}{2*9}=\frac{-42}{18}
=-2+1/3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+15}{2*9}=\frac{-12}{18}
=-2/3
$